This AVL tree is unbalanced, since the balance factor for node 6 is -2. I have an assignment, to implement a method which prints out the balance factor of all the internal nodes of the binary tree t. I have tried to do it, but I needed three methods.. But we can fix it! For purposes of implementing an AVL tree, and gaining the benefit of having a balanced tree we will define a tree to be in balance if the balance factor is -1, 0, or 1. The balance factor of any node of an AVL tree is in the integer range [-1,+1]. In Data Structures, AVL tree (Adelson-Velsky and Landis tree) is a height-balanced binary search tree in which difference between the heights of left subtree and right subtree can be atmost 1. For a given node N, the absolute difference between the heights of its left and right sub tree is either zero or one. The difference between the heights can be termed as the balance factor. I’ve marked the balance factor … Therefore, we can calculate the new balances of "A" and "B" as follows (ht is the height function): NewBal(A) = ht(b) - … AVL Tree Rotations. This difference is called the Balance Factor. The above height-balancing scheme is used in AVL trees. Each node of the AVL Tree maintains a specific relation between its left and right sub trees. It is a binary search tree where each node associated with a balance factor. AVL tree checks the height of the left and the right sub-trees and assures that the difference is not more than 1. If after any modification in the tree, the balance factor becomes less than −1 or greater than +1, the subtree rooted at this node is unbalanced, and a rotation is needed. Calculating it each time would completely destroy the advantages of using an AVL tree in the first place. And the second part is getting the balance factor of a sub-tree in an AVL tree, I've got no problem understanding the concept, "get the height of your L and R sub-trees and subtract R from L". The height of an AVL tree is always O(Logn) where n is the number of nodes in the tree. Sandeep Verma; Articles . And this is defined as something like this: BALANCE = NODE[L][HEIGHT] - NODE[R][HEIGT] The "balance" of a tree is the height of its right subtree less the height of its left subtree. Rebalancing operates on a root node and is only carried out depending on the balance factor … Instead, add a variable to each node which stores the height of the tree rooted at that node. If the balance factor is zero then the tree is perfectly in balance. Then, whenever you need to know the balance factor of a node you simply use the definition of balance factor and the heights of its children. Have a look at this AVL tree. 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